Voorbeeld 1 - Math4MBO

Bereken, denk om de voorrangsregels:

$5 xx sqrt(12^2 + 5^2) - 3 + 2^4$
$5 xx sqrt(12^2) + sqrt(5^2) - (3 + 2)^4$
$5 xx sqrt(12^2 + 5^2) // 3 + 2^4$
$(5 xx sqrt(12^2 + 5^2)) /(3 + 2^4)$
$5 - sqrt(12^2 + 5^2) - 3 xx text(-)2^4$
$5 - sqrt(12^2 + 5^2) - (3 xx text(-)2)^4$

$5 xx sqrt(12^2 + 5^2) - 3 + 2^4 = 5 xx sqrt(169) - 3 + 16 =$ $5xx13 - 3 + 16 =65 - 3 + 16 = 78$
$5 xx sqrt(12^2) + sqrt(5^2) - (3 + 2)^4 = 5 xx 12 + 5 - 5^4 =$ $60 + 5 - 625 =text(-)560$
$5 xx sqrt(12^2 + 5^2) // 3 + 2^4 = 5 xx sqrt(169)//3 + 16 =$ $5 xx 13 //3 + 16 =65/3 + 48/3 = 113/3$
$(5 xx sqrt(12^2 + 5^2)) /(3 + 2^4) = (5 xx sqrt(169))/(3+16) = (5xx13)/(19) = 65/19$
$5 - sqrt(12^2 + 5^2) - 3 xx text(-)2^4 = 5 - sqrt(169) - 3 xx text(-)16 =$ $5 - 13 + 48 =40$
$5 - sqrt(12^2 + 5^2) - (3 xx text(-)2)^4 = 5 - sqrt(169) - (text(-)6)^4 =$ $5 - 13 - 1296 = text(-)1304$